My roster

Enter your player tag and the site hides everything you cannot play anyway: brawlers you are missing, and those below power 9 — below 11 from Mythic upwards. The tag goes to the official API once and then stays in your browser. It is neither stored nor logged here, and there is no account.

You can find your tag in the game, under your name in your profile.

← Overview

Prestige 2: 8 of 14 running maps — showing what is Strong pick, Good pick here. The other 6 are running too, but do not reach this tier. Show all 14.

#1 New map in: 13h 5m
Brawl Ball Deadlock
60.9% 7,476 games · at least 59.6%Strong pick
#2 New map in: 7h 5m
Knockout Please Remain Standing
59.3% 1,594 games · at least 56.1%Good pick
#3 New map in: 1h 5m
Solo Showdown Rockwall Brawl
59.9% 867 games · at least 55.2%Strong pick
#4 New map in: 1h 5m
Knockout Healthy Middle Ground
63.3% 365 games · at least 54.9%Good pick
#5 New map in: 15h 5m
Air Hockey Super Center
55.0% 2,614 games · at least 52.9%Good pick
#6 New map in: 9h 5m
Deathmatch WALKING ON HOT SAND
56.2% 1,026 games · at least 52.5%Good pick
#7 New map in: 17h 5m
Knockout 5V5 Rastermind
52.6% 1,285 games · at least 49.7%Good pick
#8 New map in: 19h 5m
Brawl Arena Crimson Divide
52.5% 779 games · at least 48.8%Good pick

What is not here

Wins are measured, not trophies. How many trophies a win brings depends on the brawler's trophy count — high up little gain and much loss, low down the other way round. That count is in none of the battles the API hands out, so this page cannot know it. It answers “where do you win most often”, not “where do you climb fastest”. The two only converge above 50%, and there the order is the same.

Showdown counts something other than a win. There is none there; what is counted is a battle ending with a trophy gain — solo places 1 to 3, in duo and trio places 1 to 2. For this page that is closer to the question than elsewhere, but it does not make the number comparable to team modes. That is why the rating on the card compares within the mode and not across all of them.